"Steady_T" analyzes P2O production potential

Let's look at that claim shall we.

Plastic has a density of .35 to .45 lbs/cu in.

http://wiki.answers.com/Q/What_is_the_density_of_plastic

So let's work backwards from 20 tons / day.

20 tons / 24 hrs per day = .833 tones / hour.

one ton = 2000 lbs * .833 = 1666 lbs / hr.

1666 lbs / .40 lbs/cu in = 4165 Cu in plastic

1 cu ft = 1728 cu in

4165 cu in / 1728 cu in per cu ft = 2.4 cu ft of plastic per hr.

So let's assume that the machine only runs 12 hr out of a 24 hr day. That means that in a 12 hr day to get plastic into the machine at a 20 ton per 12 hr day rate plastic has to be feed in at the rate of 4.8 cu ft / hr.

4.8 cu ft /per hr doesn't seem like a lot so lets see how many cu in per minute that is.

4.8 cu ft * 1728 cu in = 8294 cu in. Divided by 60 minutes per hr = 138.24 cu in per minute.

That is a 5.12in cube fed into the processor every minute.

That seems like a pretty small amount of plastic going into the processor every minute......a 5 in cube.

To put this in terms people are more familiar with it turns out that a cu in = .02 quart. So 138 cu in * .02 = 2.76 quarts volume per minute to give a 20 ton per 12 hour rate.

That doesn't seem like a a very high feed rate to me to get 20 tons of plastic into a processor in 12 hour period. 2.76 quarts per minute.

Of course if the really do that in a 24 hour period the feed rate is 1/2 of that number or about 1.38 quarts of material per minute.

So jjsmith please tell me if your statement stands up to analysis.... "My theory is that if you saw how slow it goes into the machine it would be easy to disprove the claim that it can process 20 tons of plastic per day.."



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